1. Leave one switch one for a few minutes until the corresponding bulb in the attic gets hot. Then flip it off, flip another one on and go upstairs. Then you have an off-bulb, an on-bulb, and a warm-bulb.
2. The Petri dish will be full at 12:44.
3. Alright, this one's really complicated, but here go's: The wisest one must have thought like this:
I see all hands up and 2 red dots, so I can have
either a blue or a red dot. If I had a blue one, the other 2 guys would
see all hands up and one red and one blue dot. So they would have to
think that if the second one of them (the other with red dot) sees the
same blue dot, then he must see a red dot on the first one with red dot.
However, they were both silent (and they are wise), so I have a red dot
on my forehead.
Here is another way to explain it:
All three of us (A, B, and C (me)) see everyone's hand
up, which means that everyone can see at least one red dot on someone's
head. If C has a blue dot on his head then both A and B see three hands
up, one red dot (the only way they can raise their hands), and one blue
dot (on C's, my, head). Therefore, A and B would both think this way:
if the other guys' hands are up, and I see one blue dot and one red dot,
then the guy with the red dot must raise his hand because he sees a red
dot somewhere, and that can only mean that he sees it on my head, which
would mean that I have a red dot on my head. But neither A nor B say
anything, which means that they cannot be so sure, as they would be if
they saw a blue dot on my head. If they do not see a blue dot on my
head, then they see a red dot. So I have a red dot on my forehead.
4. (Here's another answer you'll have to focus on for a while) The important thing in this riddle is that all masters had equal chances
to win. If one of them had been given a black hat and the other white
hats, the one with black hat would immediately have known his color
(unlike the others). So 1 black and 2 white hats is not a fair
distribution.
If there had been one white and two black hats
distributed, then the two with black hats would have had advantage. They
would have been able to see one black and one white hat and supposing
they had been given white hat, then the one with black hat must at once
react as in the previous situation. However, if he had remained silent,
then the guys with black hats would have known that they wear black
hats, whereas the one with white hat would have been forced to eternal
thinking with no clear answer. So neither this is a fair situation.
That's why the only way of giving each master an equal
chance is to distribute hats of one color - so 3 black hats.
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